Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct.
Example 1:
Input:nums = [1,2,3,1]
Output:true
Explanation:
The element 1 occurs at the indices 0 and 3.
Example 2:
Input:nums = [1,2,3,4]
Output:false
Explanation:
All elements are distinct.
Example 3:
Input:nums = [1,1,1,3,3,4,3,2,4,2]
Output:true
Constraints:
1 <= nums.length <= 105-109 <= nums[i] <= 1091class Solution:
2 def containsDuplicate(self, nums: List[int]) -> bool:
3 maps={}
4 for i in nums:
5 if i in maps:
6 return True
7 maps[i]=True
8
9 return False